Hooke’s law states that the force required to extend or compress a spring by some distance is directly proportional to that distance. The stiffness of the spring is a constant factor characteristic. The property of elasticity states that it takes twice the much force to stretch a spring twice as long. This linear dependence of displacement on stretching is known as Hooke’s law. This law is named after 17th century British physicist Robert Hooke.

It says that the amount of stress we apply on any object, that amount of stress is observed on it, which means Stress Strain.

Hooke's Law

Hooke’s Law Formula is given as

F = -K x


F = amount of force applied in N,

x = displacement in the spring in m,

k = spring constant or force constant.

Hooke’s law formula can be applied to determine the force constant, displacement and force in a stretched spring.

Example 1

A spring is stretched by 10 cm and has a force constant of 2 cm /dyne. Determine the Force applied.


Given parameters are

Force constant k is 2 cm/dyne,

Extension x = 10 cm.

The force applied formula is given by

F = – k x

= – 2 × 10 cm

= – 20 cm/dyne

Example 2

Determine the force constant if a force of 100 N is stretching a spring by 0.8 m.


Given parameters are

Force F = 100 N,

Extension, x = 0.2 m.

the force constant formula is given by

k = – F / x

= – 100 / 0.8

= – 125 N/m.


Give A message for us

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Google+ photo

You are commenting using your Google+ account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s